3.273 \(\int \frac{1}{1-\sinh ^5(x)} \, dx\)
Optimal. Leaf size=228 \[ -\frac{2 \tanh ^{-1}\left (\frac{(-1)^{3/5}-\tanh \left (\frac{x}{2}\right )}{\sqrt{1-\sqrt [5]{-1}}}\right )}{5 \sqrt{1-\sqrt [5]{-1}}}+\frac{1}{5} \sqrt{2} \tanh ^{-1}\left (\frac{\tanh \left (\frac{x}{2}\right )+1}{\sqrt{2}}\right )+\frac{2 \tanh ^{-1}\left (\frac{\tanh \left (\frac{x}{2}\right )+(-1)^{4/5}}{\sqrt{1-(-1)^{3/5}}}\right )}{5 \sqrt{1-(-1)^{3/5}}}-\frac{2 \sqrt [10]{-1} \tanh ^{-1}\left (\frac{(-1)^{3/10} \left ((-1)^{4/5} \tanh \left (\frac{x}{2}\right )+1\right )}{\sqrt{\sqrt [5]{-1}+(-1)^{3/5}}}\right )}{5 \sqrt{\sqrt [5]{-1}+(-1)^{3/5}}}-\frac{2 \sqrt [10]{-1} \tan ^{-1}\left (\frac{\sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )+i}{\sqrt{1-\sqrt [5]{-1}}}\right )}{5 \sqrt{1-\sqrt [5]{-1}}} \]
[Out]
(-2*(-1)^(1/10)*ArcTan[(I + (-1)^(1/10)*Tanh[x/2])/Sqrt[1 - (-1)^(1/5)]])/(5*Sqrt[1 - (-1)^(1/5)]) - (2*ArcTan
h[((-1)^(3/5) - Tanh[x/2])/Sqrt[1 - (-1)^(1/5)]])/(5*Sqrt[1 - (-1)^(1/5)]) + (Sqrt[2]*ArcTanh[(1 + Tanh[x/2])/
Sqrt[2]])/5 + (2*ArcTanh[((-1)^(4/5) + Tanh[x/2])/Sqrt[1 - (-1)^(3/5)]])/(5*Sqrt[1 - (-1)^(3/5)]) - (2*(-1)^(1
/10)*ArcTanh[((-1)^(3/10)*(1 + (-1)^(4/5)*Tanh[x/2]))/Sqrt[(-1)^(1/5) + (-1)^(3/5)]])/(5*Sqrt[(-1)^(1/5) + (-1
)^(3/5)])
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Rubi [A] time = 0.417044, antiderivative size = 228, normalized size of antiderivative = 1.,
number of steps used = 17, number of rules used = 6, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.6, Rules used =
{3213, 2660, 618, 204, 617, 206} \[ -\frac{2 \tanh ^{-1}\left (\frac{(-1)^{3/5}-\tanh \left (\frac{x}{2}\right )}{\sqrt{1-\sqrt [5]{-1}}}\right )}{5 \sqrt{1-\sqrt [5]{-1}}}+\frac{1}{5} \sqrt{2} \tanh ^{-1}\left (\frac{\tanh \left (\frac{x}{2}\right )+1}{\sqrt{2}}\right )+\frac{2 \tanh ^{-1}\left (\frac{\tanh \left (\frac{x}{2}\right )+(-1)^{4/5}}{\sqrt{1-(-1)^{3/5}}}\right )}{5 \sqrt{1-(-1)^{3/5}}}-\frac{2 \sqrt [10]{-1} \tanh ^{-1}\left (\frac{(-1)^{3/10} \left ((-1)^{4/5} \tanh \left (\frac{x}{2}\right )+1\right )}{\sqrt{\sqrt [5]{-1}+(-1)^{3/5}}}\right )}{5 \sqrt{\sqrt [5]{-1}+(-1)^{3/5}}}-\frac{2 \sqrt [10]{-1} \tan ^{-1}\left (\frac{\sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )+i}{\sqrt{1-\sqrt [5]{-1}}}\right )}{5 \sqrt{1-\sqrt [5]{-1}}} \]
Antiderivative was successfully verified.
[In]
Int[(1 - Sinh[x]^5)^(-1),x]
[Out]
(-2*(-1)^(1/10)*ArcTan[(I + (-1)^(1/10)*Tanh[x/2])/Sqrt[1 - (-1)^(1/5)]])/(5*Sqrt[1 - (-1)^(1/5)]) - (2*ArcTan
h[((-1)^(3/5) - Tanh[x/2])/Sqrt[1 - (-1)^(1/5)]])/(5*Sqrt[1 - (-1)^(1/5)]) + (Sqrt[2]*ArcTanh[(1 + Tanh[x/2])/
Sqrt[2]])/5 + (2*ArcTanh[((-1)^(4/5) + Tanh[x/2])/Sqrt[1 - (-1)^(3/5)]])/(5*Sqrt[1 - (-1)^(3/5)]) - (2*(-1)^(1
/10)*ArcTanh[((-1)^(3/10)*(1 + (-1)^(4/5)*Tanh[x/2]))/Sqrt[(-1)^(1/5) + (-1)^(3/5)]])/(5*Sqrt[(-1)^(1/5) + (-1
)^(3/5)])
Rule 3213
Int[((a_) + (b_.)*((c_.)*sin[(e_.) + (f_.)*(x_)])^(n_))^(p_), x_Symbol] :> Int[ExpandTrig[(a + b*(c*sin[e + f*
x])^n)^p, x], x] /; FreeQ[{a, b, c, e, f, n}, x] && (IGtQ[p, 0] || (EqQ[p, -1] && IntegerQ[n]))
Rule 2660
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = FreeFactors[Tan[(c + d*x)/2], x]}, Dis
t[(2*e)/d, Subst[Int[1/(a + 2*b*e*x + a*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}, x] &&
NeQ[a^2 - b^2, 0]
Rule 618
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]
Rule 204
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])
Rule 617
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]
Rule 206
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])
Rubi steps
\begin{align*} \int \frac{1}{1-\sinh ^5(x)} \, dx &=\int \left (\frac{\sqrt [10]{-1}}{5 \left (\sqrt [10]{-1}-i \sinh (x)\right )}+\frac{\sqrt [10]{-1}}{5 \left (\sqrt [10]{-1}-\sqrt [10]{-1} \sinh (x)\right )}+\frac{\sqrt [10]{-1}}{5 \left (\sqrt [10]{-1}+(-1)^{3/10} \sinh (x)\right )}+\frac{\sqrt [10]{-1}}{5 \left (\sqrt [10]{-1}+(-1)^{7/10} \sinh (x)\right )}+\frac{\sqrt [10]{-1}}{5 \left (\sqrt [10]{-1}-(-1)^{9/10} \sinh (x)\right )}\right ) \, dx\\ &=\frac{1}{5} \sqrt [10]{-1} \int \frac{1}{\sqrt [10]{-1}-i \sinh (x)} \, dx+\frac{1}{5} \sqrt [10]{-1} \int \frac{1}{\sqrt [10]{-1}-\sqrt [10]{-1} \sinh (x)} \, dx+\frac{1}{5} \sqrt [10]{-1} \int \frac{1}{\sqrt [10]{-1}+(-1)^{3/10} \sinh (x)} \, dx+\frac{1}{5} \sqrt [10]{-1} \int \frac{1}{\sqrt [10]{-1}+(-1)^{7/10} \sinh (x)} \, dx+\frac{1}{5} \sqrt [10]{-1} \int \frac{1}{\sqrt [10]{-1}-(-1)^{9/10} \sinh (x)} \, dx\\ &=\frac{1}{5} \left (2 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [10]{-1}-2 i x-\sqrt [10]{-1} x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )+\frac{1}{5} \left (2 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [10]{-1}-2 \sqrt [10]{-1} x-\sqrt [10]{-1} x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )+\frac{1}{5} \left (2 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [10]{-1}+2 (-1)^{3/10} x-\sqrt [10]{-1} x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )+\frac{1}{5} \left (2 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [10]{-1}+2 (-1)^{7/10} x-\sqrt [10]{-1} x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )+\frac{1}{5} \left (2 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [10]{-1}-2 (-1)^{9/10} x-\sqrt [10]{-1} x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )\\ &=\frac{2}{5} \operatorname{Subst}\left (\int \frac{1}{2-x^2} \, dx,x,1+\tanh \left (\frac{x}{2}\right )\right )-\frac{1}{5} \left (4 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (1-\sqrt [5]{-1}\right )-x^2} \, dx,x,-2 i-2 \sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )\right )-\frac{1}{5} \left (4 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{4 \sqrt [5]{-1} \left (1-\sqrt [5]{-1}\right )-x^2} \, dx,x,2 (-1)^{7/10}-2 \sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )\right )-\frac{1}{5} \left (4 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{4 \sqrt [5]{-1} \left (1-(-1)^{3/5}\right )-x^2} \, dx,x,-2 (-1)^{9/10}-2 \sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )\right )-\frac{1}{5} \left (4 \sqrt [10]{-1}\right ) \operatorname{Subst}\left (\int \frac{1}{4 \left (\sqrt [5]{-1}+(-1)^{3/5}\right )-x^2} \, dx,x,2 (-1)^{3/10}-2 \sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )\right )\\ &=-\frac{2 \sqrt [10]{-1} \tan ^{-1}\left (\frac{i+\sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )}{\sqrt{1-\sqrt [5]{-1}}}\right )}{5 \sqrt{1-\sqrt [5]{-1}}}-\frac{2 \tanh ^{-1}\left (\frac{(-1)^{3/5}-\tanh \left (\frac{x}{2}\right )}{\sqrt{1-\sqrt [5]{-1}}}\right )}{5 \sqrt{1-\sqrt [5]{-1}}}+\frac{1}{5} \sqrt{2} \tanh ^{-1}\left (\frac{1+\tanh \left (\frac{x}{2}\right )}{\sqrt{2}}\right )+\frac{2 \tanh ^{-1}\left (\frac{(-1)^{4/5}+\tanh \left (\frac{x}{2}\right )}{\sqrt{1-(-1)^{3/5}}}\right )}{5 \sqrt{1-(-1)^{3/5}}}-\frac{2 \sqrt [10]{-1} \tanh ^{-1}\left (\frac{(-1)^{3/10}-\sqrt [10]{-1} \tanh \left (\frac{x}{2}\right )}{\sqrt{\sqrt [5]{-1}+(-1)^{3/5}}}\right )}{5 \sqrt{\sqrt [5]{-1}+(-1)^{3/5}}}\\ \end{align*}
Mathematica [C] time = 0.868295, size = 437, normalized size = 1.92 \[ \frac{1}{10} \left (\text{RootSum}\left [\text{$\#$1}^8+2 \text{$\#$1}^7+2 \text{$\#$1}^5+14 \text{$\#$1}^4-2 \text{$\#$1}^3-2 \text{$\#$1}+1\& ,\frac{\text{$\#$1}^6 x+4 \text{$\#$1}^5 x+9 \text{$\#$1}^4 x+24 \text{$\#$1}^3 x-9 \text{$\#$1}^2 x+2 \text{$\#$1}^6 \log \left (-\text{$\#$1} \sinh \left (\frac{x}{2}\right )+\text{$\#$1} \cosh \left (\frac{x}{2}\right )-\sinh \left (\frac{x}{2}\right )-\cosh \left (\frac{x}{2}\right )\right )+8 \text{$\#$1}^5 \log \left (-\text{$\#$1} \sinh \left (\frac{x}{2}\right )+\text{$\#$1} \cosh \left (\frac{x}{2}\right )-\sinh \left (\frac{x}{2}\right )-\cosh \left (\frac{x}{2}\right )\right )+18 \text{$\#$1}^4 \log \left (-\text{$\#$1} \sinh \left (\frac{x}{2}\right )+\text{$\#$1} \cosh \left (\frac{x}{2}\right )-\sinh \left (\frac{x}{2}\right )-\cosh \left (\frac{x}{2}\right )\right )+48 \text{$\#$1}^3 \log \left (-\text{$\#$1} \sinh \left (\frac{x}{2}\right )+\text{$\#$1} \cosh \left (\frac{x}{2}\right )-\sinh \left (\frac{x}{2}\right )-\cosh \left (\frac{x}{2}\right )\right )-18 \text{$\#$1}^2 \log \left (-\text{$\#$1} \sinh \left (\frac{x}{2}\right )+\text{$\#$1} \cosh \left (\frac{x}{2}\right )-\sinh \left (\frac{x}{2}\right )-\cosh \left (\frac{x}{2}\right )\right )+4 \text{$\#$1} x+8 \text{$\#$1} \log \left (-\text{$\#$1} \sinh \left (\frac{x}{2}\right )+\text{$\#$1} \cosh \left (\frac{x}{2}\right )-\sinh \left (\frac{x}{2}\right )-\cosh \left (\frac{x}{2}\right )\right )-2 \log \left (-\text{$\#$1} \sinh \left (\frac{x}{2}\right )+\text{$\#$1} \cosh \left (\frac{x}{2}\right )-\sinh \left (\frac{x}{2}\right )-\cosh \left (\frac{x}{2}\right )\right )-x}{4 \text{$\#$1}^7+7 \text{$\#$1}^6+5 \text{$\#$1}^4+28 \text{$\#$1}^3-3 \text{$\#$1}^2-1}\& \right ]+2 \sqrt{2} \tanh ^{-1}\left (\frac{\tanh \left (\frac{x}{2}\right )+1}{\sqrt{2}}\right )\right ) \]
Antiderivative was successfully verified.
[In]
Integrate[(1 - Sinh[x]^5)^(-1),x]
[Out]
(2*Sqrt[2]*ArcTanh[(1 + Tanh[x/2])/Sqrt[2]] + RootSum[1 - 2*#1 - 2*#1^3 + 14*#1^4 + 2*#1^5 + 2*#1^7 + #1^8 & ,
(-x - 2*Log[-Cosh[x/2] - Sinh[x/2] + Cosh[x/2]*#1 - Sinh[x/2]*#1] + 4*x*#1 + 8*Log[-Cosh[x/2] - Sinh[x/2] + C
osh[x/2]*#1 - Sinh[x/2]*#1]*#1 - 9*x*#1^2 - 18*Log[-Cosh[x/2] - Sinh[x/2] + Cosh[x/2]*#1 - Sinh[x/2]*#1]*#1^2
+ 24*x*#1^3 + 48*Log[-Cosh[x/2] - Sinh[x/2] + Cosh[x/2]*#1 - Sinh[x/2]*#1]*#1^3 + 9*x*#1^4 + 18*Log[-Cosh[x/2]
- Sinh[x/2] + Cosh[x/2]*#1 - Sinh[x/2]*#1]*#1^4 + 4*x*#1^5 + 8*Log[-Cosh[x/2] - Sinh[x/2] + Cosh[x/2]*#1 - Si
nh[x/2]*#1]*#1^5 + x*#1^6 + 2*Log[-Cosh[x/2] - Sinh[x/2] + Cosh[x/2]*#1 - Sinh[x/2]*#1]*#1^6)/(-1 - 3*#1^2 + 2
8*#1^3 + 5*#1^4 + 7*#1^6 + 4*#1^7) & ])/10
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Maple [C] time = 0.036, size = 124, normalized size = 0.5 \begin{align*}{\frac{2}{5}\sum _{{\it \_R}={\it RootOf} \left ({{\it \_Z}}^{8}-2\,{{\it \_Z}}^{7}-2\,{{\it \_Z}}^{5}+14\,{{\it \_Z}}^{4}+2\,{{\it \_Z}}^{3}+2\,{\it \_Z}+1 \right ) }{\frac{-2\,{{\it \_R}}^{6}+3\,{{\it \_R}}^{5}+2\,{{\it \_R}}^{4}-2\,{{\it \_R}}^{3}-2\,{{\it \_R}}^{2}+3\,{\it \_R}+2}{4\,{{\it \_R}}^{7}-7\,{{\it \_R}}^{6}-5\,{{\it \_R}}^{4}+28\,{{\it \_R}}^{3}+3\,{{\it \_R}}^{2}+1}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -{\it \_R} \right ) }}+{\frac{\sqrt{2}}{5}{\it Artanh} \left ({\frac{\sqrt{2}}{4} \left ( 2\,\tanh \left ( x/2 \right ) +2 \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(1/(1-sinh(x)^5),x)
[Out]
2/5*sum((-2*_R^6+3*_R^5+2*_R^4-2*_R^3-2*_R^2+3*_R+2)/(4*_R^7-7*_R^6-5*_R^4+28*_R^3+3*_R^2+1)*ln(tanh(1/2*x)-_R
),_R=RootOf(_Z^8-2*_Z^7-2*_Z^5+14*_Z^4+2*_Z^3+2*_Z+1))+1/5*2^(1/2)*arctanh(1/4*(2*tanh(1/2*x)+2)*2^(1/2))
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{10} \, \sqrt{2} \log \left (-\frac{\sqrt{2} - e^{x} + 1}{\sqrt{2} + e^{x} - 1}\right ) + \int \frac{2 \,{\left (e^{\left (7 \, x\right )} + 4 \, e^{\left (6 \, x\right )} + 9 \, e^{\left (5 \, x\right )} + 24 \, e^{\left (4 \, x\right )} - 9 \, e^{\left (3 \, x\right )} + 4 \, e^{\left (2 \, x\right )} - e^{x}\right )}}{5 \,{\left (e^{\left (8 \, x\right )} + 2 \, e^{\left (7 \, x\right )} + 2 \, e^{\left (5 \, x\right )} + 14 \, e^{\left (4 \, x\right )} - 2 \, e^{\left (3 \, x\right )} - 2 \, e^{x} + 1\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(1-sinh(x)^5),x, algorithm="maxima")
[Out]
-1/10*sqrt(2)*log(-(sqrt(2) - e^x + 1)/(sqrt(2) + e^x - 1)) + integrate(2/5*(e^(7*x) + 4*e^(6*x) + 9*e^(5*x) +
24*e^(4*x) - 9*e^(3*x) + 4*e^(2*x) - e^x)/(e^(8*x) + 2*e^(7*x) + 2*e^(5*x) + 14*e^(4*x) - 2*e^(3*x) - 2*e^x +
1), x)
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Fricas [B] time = 4.08645, size = 11359, normalized size = 49.82 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(1-sinh(x)^5),x, algorithm="fricas")
[Out]
1/200*sqrt(2)*sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + 20)*(8*sqrt(5) + 24)^(1/4)*(3*sqr
t(5) - 5)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3)*arctan(1/40*sqrt(2)*((11*sqrt(5) - 25)*e^x + 7*sqrt(5) - 15)*s
qrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 1/80*sqrt(2)*(sqrt(2)*((11*sqrt(5) - 25)*e^x - 4*sqrt(5) + 10)*sqrt(2*s
qrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*((3*sqrt(5) - 5)*e^x - 7*sqrt(5) + 15)*sqrt(2*sqrt(5) + 5))*sqrt(sqrt(5) + 3
) + 1/12800*(80*sqrt(2)*(5*sqrt(5) - 11)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 40*sqrt(2)*(sqrt(2)*(5*sqrt(5
) - 11)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*sqrt(2*sqrt(5) + 5)*(sqrt(5) - 3))*sqrt(sqrt(5) + 3) + sqrt(
2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + 20)*((sqrt(2)*(7*sqrt(5) - 15)*sqrt(2*sqrt(5) + 5)*s
qrt(sqrt(5) + 3) + 2*(11*sqrt(5) - 25)*sqrt(2*sqrt(5) + 5))*(8*sqrt(5) + 24)^(3/4) + 4*(sqrt(2)*(17*sqrt(5) -
35)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*(11*sqrt(5) - 25)*sqrt(2*sqrt(5) + 5))*(8*sqrt(5) + 24)^(1/4)) +
320*sqrt(2*sqrt(5) + 5)*(sqrt(5) - 4))*sqrt(-20*sqrt(2)*sqrt(sqrt(5) + 3)*(sqrt(5) - 3) - 40*(sqrt(5) - 1)*e^
x + 2*(sqrt(2)*((2*sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*sqrt(sqrt(5) + 3) + 2*(sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*
sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + 20)*(8*sqrt(5) + 24)^(1/4) + 80*e^(2*x) + 80) +
1/640*sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + 20)*((sqrt(2)*((3*sqrt(5) - 7)*e^x - 8*s
qrt(5) + 18)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*((5*sqrt(5) - 11)*e^x - 2*sqrt(5) + 4)*sqrt(2*sqrt(5) +
5))*(8*sqrt(5) + 24)^(3/4) + 4*(sqrt(2)*((7*sqrt(5) - 17)*e^x - 8*sqrt(5) + 18)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt
(5) + 3) + 2*((5*sqrt(5) - 11)*e^x - 5*sqrt(5) + 9)*sqrt(2*sqrt(5) + 5))*(8*sqrt(5) + 24)^(1/4)) + 1/20*(2*(4*
sqrt(5) - 5)*e^x + sqrt(5) - 5)*sqrt(2*sqrt(5) + 5)) + 1/200*sqrt(2)*sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(
5) + 3) - 4*sqrt(5) + 20)*(8*sqrt(5) + 24)^(1/4)*(3*sqrt(5) - 5)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3)*arctan(
-1/40*sqrt(2)*((11*sqrt(5) - 25)*e^x + 7*sqrt(5) - 15)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) - 1/80*sqrt(2)*(s
qrt(2)*((11*sqrt(5) - 25)*e^x - 4*sqrt(5) + 10)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*((3*sqrt(5) - 5)*e^x
- 7*sqrt(5) + 15)*sqrt(2*sqrt(5) + 5))*sqrt(sqrt(5) + 3) - 1/12800*(80*sqrt(2)*(5*sqrt(5) - 11)*sqrt(2*sqrt(5
) + 5)*sqrt(sqrt(5) + 3) + 40*sqrt(2)*(sqrt(2)*(5*sqrt(5) - 11)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*sqrt
(2*sqrt(5) + 5)*(sqrt(5) - 3))*sqrt(sqrt(5) + 3) - sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sqrt(5
) + 20)*((sqrt(2)*(7*sqrt(5) - 15)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*(11*sqrt(5) - 25)*sqrt(2*sqrt(5)
+ 5))*(8*sqrt(5) + 24)^(3/4) + 4*(sqrt(2)*(17*sqrt(5) - 35)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*(11*sqrt
(5) - 25)*sqrt(2*sqrt(5) + 5))*(8*sqrt(5) + 24)^(1/4)) + 320*sqrt(2*sqrt(5) + 5)*(sqrt(5) - 4))*sqrt(-20*sqrt(
2)*sqrt(sqrt(5) + 3)*(sqrt(5) - 3) - 40*(sqrt(5) - 1)*e^x - 2*(sqrt(2)*((2*sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*s
qrt(sqrt(5) + 3) + 2*(sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*s
qrt(5) + 20)*(8*sqrt(5) + 24)^(1/4) + 80*e^(2*x) + 80) + 1/640*sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3
) - 4*sqrt(5) + 20)*((sqrt(2)*((3*sqrt(5) - 7)*e^x - 8*sqrt(5) + 18)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2
*((5*sqrt(5) - 11)*e^x - 2*sqrt(5) + 4)*sqrt(2*sqrt(5) + 5))*(8*sqrt(5) + 24)^(3/4) + 4*(sqrt(2)*((7*sqrt(5) -
17)*e^x - 8*sqrt(5) + 18)*sqrt(2*sqrt(5) + 5)*sqrt(sqrt(5) + 3) + 2*((5*sqrt(5) - 11)*e^x - 5*sqrt(5) + 9)*sq
rt(2*sqrt(5) + 5))*(8*sqrt(5) + 24)^(1/4)) - 1/20*(2*(4*sqrt(5) - 5)*e^x + sqrt(5) - 5)*sqrt(2*sqrt(5) + 5)) -
1/400*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 20)*(3*sqrt(5) + 5)*sqrt(-2*sqrt(5) + 5)*(-8*
sqrt(5) + 24)^(3/4)*arctan(-1/1280*((4*(5*sqrt(5) + 11)*e^x + ((3*sqrt(5) + 7)*e^x - 8*sqrt(5) - 18)*sqrt(-8*s
qrt(5) + 24) - 8*sqrt(5) - 16)*(-8*sqrt(5) + 24)^(3/4) + 4*(4*(5*sqrt(5) + 11)*e^x + ((7*sqrt(5) + 17)*e^x - 8
*sqrt(5) - 18)*sqrt(-8*sqrt(5) + 24) - 20*sqrt(5) - 36)*(-8*sqrt(5) + 24)^(1/4))*sqrt(-(2*sqrt(5) + 5)*sqrt(-8
*sqrt(5) + 24) + 4*sqrt(5) + 20)*sqrt(-2*sqrt(5) + 5) + 1/25600*((((7*sqrt(5) + 15)*sqrt(-8*sqrt(5) + 24) + 44
*sqrt(5) + 100)*(-8*sqrt(5) + 24)^(3/4) + 4*((17*sqrt(5) + 35)*sqrt(-8*sqrt(5) + 24) + 44*sqrt(5) + 100)*(-8*s
qrt(5) + 24)^(1/4))*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 20)*sqrt(-2*sqrt(5) + 5) - 20*((
(5*sqrt(5) + 11)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 12)*sqrt(-8*sqrt(5) + 24) + 4*(5*sqrt(5) + 11)*sqrt(-8*sq
rt(5) + 24) + 32*sqrt(5) + 128)*sqrt(-2*sqrt(5) + 5))*sqrt(40*(sqrt(5) + 1)*e^x + (4*(sqrt(5) + 5)*e^x + ((2*s
qrt(5) + 5)*e^x + 3*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 6*sqrt(5) + 10)*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5)
+ 24) + 4*sqrt(5) + 20)*(-8*sqrt(5) + 24)^(1/4) + 10*(sqrt(5) + 3)*sqrt(-8*sqrt(5) + 24) + 80*e^(2*x) + 80) +
1/320*(32*(4*sqrt(5) + 5)*e^x + 4*((11*sqrt(5) + 25)*e^x + 7*sqrt(5) + 15)*sqrt(-8*sqrt(5) + 24) + (4*(3*sqrt
(5) + 5)*e^x + ((11*sqrt(5) + 25)*e^x - 4*sqrt(5) - 10)*sqrt(-8*sqrt(5) + 24) - 28*sqrt(5) - 60)*sqrt(-8*sqrt(
5) + 24) + 16*sqrt(5) + 80)*sqrt(-2*sqrt(5) + 5)) - 1/400*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt
(5) + 20)*(3*sqrt(5) + 5)*sqrt(-2*sqrt(5) + 5)*(-8*sqrt(5) + 24)^(3/4)*arctan(-1/1280*((4*(5*sqrt(5) + 11)*e^x
+ ((3*sqrt(5) + 7)*e^x - 8*sqrt(5) - 18)*sqrt(-8*sqrt(5) + 24) - 8*sqrt(5) - 16)*(-8*sqrt(5) + 24)^(3/4) + 4*
(4*(5*sqrt(5) + 11)*e^x + ((7*sqrt(5) + 17)*e^x - 8*sqrt(5) - 18)*sqrt(-8*sqrt(5) + 24) - 20*sqrt(5) - 36)*(-8
*sqrt(5) + 24)^(1/4))*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 20)*sqrt(-2*sqrt(5) + 5) + 1/2
5600*((((7*sqrt(5) + 15)*sqrt(-8*sqrt(5) + 24) + 44*sqrt(5) + 100)*(-8*sqrt(5) + 24)^(3/4) + 4*((17*sqrt(5) +
35)*sqrt(-8*sqrt(5) + 24) + 44*sqrt(5) + 100)*(-8*sqrt(5) + 24)^(1/4))*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) +
24) + 4*sqrt(5) + 20)*sqrt(-2*sqrt(5) + 5) + 20*(((5*sqrt(5) + 11)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 12)*sq
rt(-8*sqrt(5) + 24) + 4*(5*sqrt(5) + 11)*sqrt(-8*sqrt(5) + 24) + 32*sqrt(5) + 128)*sqrt(-2*sqrt(5) + 5))*sqrt(
40*(sqrt(5) + 1)*e^x - (4*(sqrt(5) + 5)*e^x + ((2*sqrt(5) + 5)*e^x + 3*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 6*
sqrt(5) + 10)*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 20)*(-8*sqrt(5) + 24)^(1/4) + 10*(sqrt
(5) + 3)*sqrt(-8*sqrt(5) + 24) + 80*e^(2*x) + 80) - 1/320*(32*(4*sqrt(5) + 5)*e^x + 4*((11*sqrt(5) + 25)*e^x +
7*sqrt(5) + 15)*sqrt(-8*sqrt(5) + 24) + (4*(3*sqrt(5) + 5)*e^x + ((11*sqrt(5) + 25)*e^x - 4*sqrt(5) - 10)*sqr
t(-8*sqrt(5) + 24) - 28*sqrt(5) - 60)*sqrt(-8*sqrt(5) + 24) + 16*sqrt(5) + 80)*sqrt(-2*sqrt(5) + 5)) - 1/800*(
sqrt(2)*(3*sqrt(5) - 5)*sqrt(sqrt(5) + 3) + 8*sqrt(5))*sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sq
rt(5) + 20)*(8*sqrt(5) + 24)^(1/4)*log(-4*sqrt(2)*sqrt(sqrt(5) + 3)*(sqrt(5) - 3) - 8*(sqrt(5) - 1)*e^x + 2/5*
(sqrt(2)*((2*sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*sqrt(sqrt(5) + 3) + 2*(sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*sqrt(2
*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + 20)*(8*sqrt(5) + 24)^(1/4) + 16*e^(2*x) + 16) + 1/800
*(sqrt(2)*(3*sqrt(5) - 5)*sqrt(sqrt(5) + 3) + 8*sqrt(5))*sqrt(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*
sqrt(5) + 20)*(8*sqrt(5) + 24)^(1/4)*log(-4*sqrt(2)*sqrt(sqrt(5) + 3)*(sqrt(5) - 3) - 8*(sqrt(5) - 1)*e^x - 2/
5*(sqrt(2)*((2*sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*sqrt(sqrt(5) + 3) + 2*(sqrt(5) - 5)*e^x + 3*sqrt(5) - 5)*sqrt
(2*sqrt(2)*(2*sqrt(5) - 5)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + 20)*(8*sqrt(5) + 24)^(1/4) + 16*e^(2*x) + 16) - 1/1
600*((3*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 16*sqrt(5))*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(
5) + 20)*(-8*sqrt(5) + 24)^(1/4)*log(8*(sqrt(5) + 1)*e^x + 1/5*(4*(sqrt(5) + 5)*e^x + ((2*sqrt(5) + 5)*e^x + 3
*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 6*sqrt(5) + 10)*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5)
+ 20)*(-8*sqrt(5) + 24)^(1/4) + 2*(sqrt(5) + 3)*sqrt(-8*sqrt(5) + 24) + 16*e^(2*x) + 16) + 1/1600*((3*sqrt(5)
+ 5)*sqrt(-8*sqrt(5) + 24) + 16*sqrt(5))*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 20)*(-8*sqr
t(5) + 24)^(1/4)*log(8*(sqrt(5) + 1)*e^x - 1/5*(4*(sqrt(5) + 5)*e^x + ((2*sqrt(5) + 5)*e^x + 3*sqrt(5) + 5)*sq
rt(-8*sqrt(5) + 24) + 6*sqrt(5) + 10)*sqrt(-(2*sqrt(5) + 5)*sqrt(-8*sqrt(5) + 24) + 4*sqrt(5) + 20)*(-8*sqrt(5
) + 24)^(1/4) + 2*(sqrt(5) + 3)*sqrt(-8*sqrt(5) + 24) + 16*e^(2*x) + 16) + 1/10*sqrt(2)*log((2*(sqrt(2) - 1)*e
^x - 2*sqrt(2) + e^(2*x) + 3)/(e^(2*x) - 2*e^x - 1))
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(1-sinh(x)**5),x)
[Out]
Timed out
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{1}{\sinh \left (x\right )^{5} - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(1-sinh(x)^5),x, algorithm="giac")
[Out]
integrate(-1/(sinh(x)^5 - 1), x)